Challenge your understanding of advanced digital modulation techniques with questions on QPSK, QAM, and OFDM principles, applications, and signal characteristics. This quiz is designed for learners seeking to deepen their knowledge of modern communication systems and signal analysis.
Which of the following statements best describes how Quadrature Phase Shift Keying (QPSK) encodes digital data into symbols?
Explanation: QPSK transmits two bits per symbol by varying the phase of the carrier among four discrete values, each representing a unique two-bit combination. Option B describes Frequency Shift Keying, not QPSK. Option C incorrectly refers to an eight-level amplitude scheme, which is typical for 8-ASK or certain types of QAM, not QPSK. Option D confuses amplitude with phase; QPSK uses phase changes, not amplitude levels, to carry information.
In a 16-QAM modulation scheme, how many unique symbols exist in its constellation diagram, and what do they represent?
Explanation: A 16-QAM constellation contains 16 distinct symbols, and each symbol represents a unique combination of four bits since 2^4 equals 16. Option B erroneously states 8 symbols and relies solely on amplitude. Option C is incorrect because 32 symbols pertain to 32-QAM, and using phase only would align more with PSK. Option D misstates the bit count, as 16-QAM represents four, not two, bits per symbol.
Why is Orthogonal Frequency Division Multiplexing (OFDM) especially effective in environments with multipath fading, such as urban wireless channels?
Explanation: OFDM divides the transmitted data among numerous closely spaced subcarriers, each experiencing slow fading, effectively combating multipath effects and reducing inter-symbol interference. Increasing the carrier frequency (Option B) does not inherently provide multipath resistance. Reducing overall bandwidth (Option C) may make the signal more susceptible to noise, not less. Using amplitude-only modulation, as in Option D, does not address multipath fading and can even exacerbate fading issues.
Given a 64-QAM system operating at a symbol rate of 1 Mega-symbol per second, what is its raw bit rate (ignoring error correction and overhead)?
Explanation: 64-QAM uses 2^6, or 64, possible symbols; each symbol thus represents 6 bits. At a symbol rate of 1 Mega-symbol per second, the bit rate is 6 Megabits per second. Option B gives the rate for 256-QAM with 8 bits per symbol. Option C is based on 8-QAM (3 bits per symbol). Option D incorrectly multiplies the symbol rate directly by the number of symbols rather than by log2(symbols).
Which modulation scheme typically achieves higher spectral efficiency among the following, given identical noise and channel conditions?
Explanation: 64-QAM offers higher spectral efficiency because it transmits six bits per symbol, compared to 2 bits for QPSK and one bit for BPSK or OOK (On-Off Keying). While spectral efficiency should be balanced against the required signal-to-noise ratio, higher-order QAM schemes generally achieve greater bits per second per hertz. BPSK and QPSK are more robust but less efficient, and OOK is a basic form of amplitude keying, also less efficient than higher-order QAM.