Test your understanding of key Analog VLSI interview questions on passive circuits, focusing on first-order RC and RL circuits. This easy quiz will help you practice essential concepts such as time constants, voltage behavior, and intuitive analysis relevant to analog circuit interviews.
What is the time constant (τ) of an RC circuit consisting of a 1 kΩ resistor and a 1 μF capacitor connected in series?
Explanation: The time constant τ for an RC circuit is given by τ = R × C. Here, R = 1 kΩ and C = 1 μF, giving τ = 1000 × 0.000001 = 0.001 seconds or 1 millisecond. 1 microsecond is incorrect as it is too small, 1 second is too large, and 10 milliseconds is ten times the correct value.
Is it possible for the output voltage (Vout) of an RC circuit to exceed the supply voltage (VDD) in practical scenarios, and under what basic condition?
Explanation: In certain practical cases, such as rapid switching or with inductive kick-back, Vout can temporarily exceed VDD due to energy stored in inductors. Resonance does not typically occur in simple RC circuits, so option A is wrong. Saying it is 'never possible' ignores real transient behaviors. Capacitors cannot charge to a value more negative than the supply without active circuits, making option D incorrect.
For a series RC circuit, the zero in the transfer function is intuitively located at which frequency?
Explanation: The zero of the transfer function in a standard RC circuit is at s = -1/(RC) in the Laplace domain. RC or -RC are not frequencies and do not represent the location of the zero. 1/(RC) is positive, missing the negative sign required for a stable system zero.
What happens to the voltage across the capacitor in an RC circuit when a DC step input is suddenly applied (e.g., 0V to 5V)?
Explanation: A capacitor's voltage cannot change instantly; it increases gradually, approaching the final value according to the RC time constant. Instant jumping is physically impossible. It does not remain at zero or decrease toward zero unless a reverse scenario is described, so those options are incorrect.
After charging, when the supply voltage is removed from an RC circuit, how does Vout behave over time?
Explanation: Upon disconnecting the supply, the capacitor discharges through the resistor, causing Vout to decay exponentially toward zero. The voltage does not increase or stay constant. Oscillations do not occur in simple RC circuits without additional reactive components.
If a second identical capacitor is added in parallel to an existing one in an RC circuit, what will be the new time constant?
Explanation: Adding a second capacitor in parallel increases the total capacitance (C_total = C1 + C2). This doubles the capacitance, so the time constant τ = R × C_total also doubles. Halving would occur if resistance was decreased, not capacitance, so that choice is incorrect. It never becomes zero and does not remain the same.
At steady state (long after the input is applied), the capacitor in an RC circuit behaves electrically as what?
Explanation: In DC steady state, the capacitor charges fully and blocks direct current, behaving as an open circuit. Treating it as a short circuit applies only to AC at very high frequencies. It isn’t a variable resistor or current source, so those options are not appropriate.
Immediately after a DC voltage step is applied to a series RC circuit, what is true about the current through the resistor?
Explanation: At the instant a step input is applied, the capacitor initially behaves like a short circuit, so the entire supply voltage appears across the resistor, causing maximum current. The current is not zero or slowly increasing; rather, it decreases over time. It does not stay constant either.
What is the order of a simple RC circuit?
Explanation: An RC circuit has one energy storage element (the capacitor), so it is a first-order circuit. Second order requires two storage elements. Zeroth and third orders do not apply to this configuration.
If the time constant τ of an RC circuit is made very large, what is the effect on the output voltage Vout in response to a sudden input?
Explanation: A larger time constant means the capacitor charges or discharges more slowly, so Vout changes gradually after a step input. It definitely does not reach its final value immediately or change very fast. Instability is not typical in such passive circuits, making option C incorrect.