Explore fundamental concepts of Parseval’s Theorem and energy relations in signals, including applications in the time and frequency domains. Enhance your understanding of energy calculations, continuous and discrete signals, and typical misconceptions in signal analysis.
Which of the following correctly expresses Parseval’s Theorem for a continuous-time signal x(t) with Fourier Transform X(f)?
Explanation: Parseval’s Theorem states that the energy of a signal in the time domain is equal to the integral of the magnitude squared of its Fourier Transform in the frequency domain. The second option is incorrect because just summing X(f) does not give the energy. The third choice refers to multiplication in the time domain, not the correct integration in the frequency domain. The last option, using X(0), represents only the DC component, not the total energy.
If a continuous-time signal x(t) has energy E in the time domain, what is its energy in the frequency domain according to Parseval’s Theorem?
Explanation: Parseval’s Theorem ensures that the total energy calculated in the frequency domain matches that of the time domain precisely, so the answer is exactly E. Doubling or squaring the energy (options two and four) are misunderstandings of the theorem’s equality. Option three is incorrect because energy can be calculated in both domains.
For a discrete-time finite-length signal x[n], which mathematical operation does Parseval’s Theorem equate between the time and frequency domains?
Explanation: In the discrete case, Parseval’s Theorem asserts that the sum of the squared magnitude of the signal samples equals the normalized sum of the squared magnitude of the DFT coefficients. The multiplication of the sequences is not what Parseval’s relates. Summing without squaring (option three) measures a different property. The difference (option four) is never used in Parseval’s context.
What does Parseval’s Theorem physically imply about energy-preserving transformations such as the Fourier Transform?
Explanation: Parseval’s Theorem reveals that the Fourier Transform is energy-preserving, meaning the energy calculation is consistent in both domains. Transformation does not increase energy, so option two is incorrect. Option three is wrong because energy is validly computed in both domains. Option four incorrectly claims energy is determined only by the highest frequency.
A student applies Parseval’s Theorem to a signal that does not have finite energy (such as a sinusoid continuing indefinitely). Why is this application invalid?
Explanation: Parseval’s Theorem requires the signal to have finite energy, meaning it must be square-integrable; sinusoids that extend infinitely do not meet this requirement. The claim that sinusoids have no frequency-domain representation is false because they do, but with infinite energy. The theorem does not apply to all signals or require periodicity, making options three and four incorrect.