Pseudocode to Code Translation Quiz Quiz

Sharpen your programming logic with this quiz designed to test your ability to translate pseudocode into actual code. Enhance your understanding of converting algorithmic steps into correct syntactic forms for popular programming languages.

  1. Translating Conditional Statements

    Given the pseudocode: IF score u003E 50 THEN print 'Passed' ELSE print 'Failed', which Python code segment correctly implements this logic?

    1. if score u003E 50 print('Passed'); else print('Failed')
    2. if score u003E 50: print('Passed') else: print('Failed')
    3. if score u003E 50 then print('Passed') else print('Failed')
    4. if score u003E 50: print('Passed') elif: print('Failed')

    Explanation: The correct answer uses proper Python syntax by ending the if-condition with a colon and placing the else statement on the same indentation level, also with a colon. The other options contain syntax errors: one uses 'elif' incorrectly, another omits necessary colons and indentation, and a third incorrectly includes 'then', which is not Python syntax.

  2. Loop Translation Accuracy

    How would you translate the pseudocode FOR i = 1 TO 5 DO print i into a correctly functioning Java for-loop?

    1. for (int i = 1; i u003C= 5; i++) { System.out.println(i); }
    2. for (int i = 0; i u003C 5; i++) { print(i); }
    3. for (int i = 1; i u003C 5; i--) { System.out.println(i); }
    4. for (i = 1; i u003E 5; i++) { print(i); }

    Explanation: Option A matches the intended iteration from 1 to 5, incrementing i and printing each value. Option B decrements i and would cause an infinite loop. Option C uses incorrect relational operators and lacks data type declarations. Option D starts from 0 instead of 1 and uses a print statement that doesn't match Java's standard output convention.

  3. Variable Assignment Translation

    How should the pseudocode x ← y + 2 be correctly written in C++?

    1. x = y + 2;
    2. x := y + 2;
    3. x u003C- y + 2;
    4. x == y + 2;

    Explanation: In C++, assignments use the single equals sign, so 'x = y + 2;' is correct. The use of ':=' and 'u003C-' are not valid C++ syntax for assignment and come from other languages or pseudocode conventions. '==' is the comparison operator, not assignment.

  4. Translating REPEAT-UNTIL Logic

    Which segment correctly converts the pseudocode REPEAT print n; n = n - 1 UNTIL n == 0 into JavaScript?

    1. do { console.log(n) n = n - 1 } while n == 0;
    2. do { console.log(n); n = n - 1; } while (n != 0);
    3. while (n == 0) { console.log(n); n = n - 1; }
    4. for (; n == 0; n--) { console.log(n); }

    Explanation: A do-while loop in JavaScript executes at least once and continues until the condition becomes false, which matches the REPEAT-UNTIL logic. Option A switches 'UNTIL n == 0' to 'while (n != 0)', which is correct. The other options misuse loop structures, comparison operators, missing semicolons, or have syntax errors.

  5. Function Translation Basics

    If the pseudocode says FUNCTION square(num) RETURNS num * num, what is the correct translation in Python?

    1. def square: num return num * num
    2. func square(num) -u003E num * num
    3. def square(num): return num * num
    4. function square(num) { return num * num }

    Explanation: Only the first option uses correct Python syntax for defining a function and returning a value. Option B uses JavaScript syntax. Options C and D misuse Python's function declaration structure or introduce incorrect keywords. Proper indentation and the 'def' keyword followed by parameters in parentheses are required in Python.